An old problem from the Soviet Mathematical Olympiad:
Find the 4-digit number aabb that is a perfect square.
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The smallest 4-digit perfect square is 1024 (322). The largest is 9801 (992). And
aabb = 1000a + 100a + 10b + b
= 1100a + 11b
= 11(100a + b).
So 11 is one of the factors of aabb, and aabb is of the form (11k)2. That leaves only six candidates to check (332, 442, 552, 662, 772, 882), and it turns out the answer is 882 = 7744.
(Thanks, Danesh.)
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