In a Word

idoneous
adj. apt, fit, or suitable

tripudiary
adj. pertaining to dancing

Hermit crabs adopt other creatures’ castoff shells for protection. But as they grow, crabs must move into successively larger shells. This produces a curious phenomenon: When a crab finds a shell that’s too big for it, it waits nearby. Other crabs may accumulate, forming a little conga line of dissatisfied shell seekers. Finally a “Goldilocks” crab arrives — a crab large enough to claim the new shell — and now each waiting crab can move into the shell abandoned by its larger neighbor. By cooperating to share a scarce resource, the whole species benefits.

The same thing happens in human societies — when one person finds a new apartment, car, or job, she leaves behind her old one, and the vacancy passes down through society until the final unit is cast away or destroyed. It’s called a vacancy chain.

(Thanks, Duncan.)

Fundamental Things Apply

casablanca

In the final scene of Casablanca, the airplane is made of plywood. The film was shot shortly after the Japanese attacked Pearl Harbor, and California was bracing for a new attack, so movie studios were severely restricted from shooting on location and forbidden entirely from filming at airports. So the movie was shot on soundstages at the Warner Bros. studios in Burbank, and Soundstage #1, as it turned out, was too small to accommodate a real airplane.

So prop men built a half-size Lockheed Electra 12A out of plywood and balsa, and little people in jumpsuits were hired to bustle around it. The fog — a rarity in Morocco — helped to sell the effect.

Also: Dooley Wilson was an accomplished singer, but he couldn’t play the piano. “During the filming of Casablanca, a Warners staff musician, Elliott Carpenter, played the piano to the side of the set so that Wilson could get his bearings,” writes Jeff Siegel in The Casablanca Companion. “It’s also Carpenter’s playing that was dubbed into the film. The charade went off so well that when Wilson appeared for a nightclub gig after the movie was released, the club’s manager asked him why he wasn’t going to play the piano in his act.”

Shifting Gears

https://commons.wikimedia.org/wiki/File:Cappiello_Jacquelin_Le_Rire_1903.jpg

A puzzle by French puzzle maven Pierre Berloquin:

Timothy rides a bicycle on a road that has four parts of equal length.

The first fourth is level, and he pedals at 10 kph.

The second fourth is uphill, and he pedals at 5 kph.

The third fourth is downhill, and he rides at 30 kph.

The fourth fourth is level again, but he has the wind at his back, so he goes 15 kph.

What is his average speed?

Click for Answer

Ergonomics

https://www.flickr.com/photos/scriptingnews/3418293087
Image: Flickr

We’ve been making things awfully hard on spirits. The standard Ouija board lays out the alphabet in two simple rows, which means it’s easy for the dead to tell us about FEEDERS but terribly hard to refer to LAYAWAY, even though these words are equally long.

In the interests of better communication, Eric Iverson made a study of this for the August 2005 issue of Word Ways. Using an image of a Ouija board, he counted the number of pixels that a planchette would have to travel in order to spell out various English words. The results are dismaying: The most exhausting four-letter word, MAMA, requires fully 17 times as much travel as the simple FEED. Longer words are more consistent: The hardest 23-letter word, DISESTABLISHMENTARIANISM, requires little more work than the easiest, ELECTROENCEPHALOGRAPHIC. But do dead people have that kind of stamina?

What’s the answer? Iverson experimented with different layouts and found a hexagonal grid that minimizes the average travel distance for a typical word (see the link below). And he found a checkerboard grid that’s 3 percent more efficient than that. Even rearranging the letters on a standard board to ZXVGINAROFUPQ JKWCHTESDLMYB rather than the standard alphabet increases efficiency by about a third. Now maybe we can have some better conversations.

(Eric Iverson, “Traveling Around the Ouija Board,” Word Ways 38:3 [August 2005], 174-177.)

The Battle of the Reed Rules

https://commons.wikimedia.org/wiki/File:Thomas_Brackett_Reed_by_John_Singer_Sargent.jpg

Until 1890, the minority party in the U.S. House of Representatives could block a vote by “disappearing”; they’d demand a roll call, remain silent when called upon, and then declare that too few members were “present” for the House to conduct its business.

To incoming speaker Thomas Brackett Reed this was a “tyranny of the minority,” and on Jan. 28 he resolved to break it. When Democrats demanded a roll call and refused to answer to their names, Reed marked them present anyway; when Kentucky representative James B. McCreary objected, Reed said sweetly, “The Chair is making a statement of fact that the gentleman from Kentucky is present. Does he deny it?”

There followed a sort of ontological shooting gallery. Democrats hid under their desks and behind screens to avoid being observed to exist. When they tried to flee the chamber entirely, Reed ordered the doors locked, which started a scramble to get out before the next vote. Representative Kilgore of Texas had to kick open a locked door to escape. Amid the howled objections, Confederate general “Fighting Joe” Wheeler came down from the rear “leaping from desk to desk as an ibex leaps from crag to crag,” and one unnamed Texas Democrat “sat in his seat significantly whetting a bowie knife on his boot.” Finally the Republicans mustered a majority even with the Democrats entirely absent, and the battle was over: Reed’s new rules were adopted on February 14.

Throughout all this Reed had seemed imperturbable, “serene as a summer morning.” He told a friend later that he had made up his mind what he would do if the House did not support him. “I would simply have left the Chair and resigned the Speakership and my seat in Congress,” he said. “I had made up my mind that if political life consisted in sitting helplessly in the Speaker’s Chair and seeing the majority helpless to pass legislation, I had had enough of it and was ready to step down and out.”

(From Barbara Tuchman’s The Proud Tower.) (Thanks, Zach.)

Podcast Episode 76: Get Out of Jail Free

https://commons.wikimedia.org/wiki/File:German_Monopoly_board_in_the_middle_of_a_game.jpg
Image: Wikimedia Commons

During World War II, the British Secret Service found a surprising way to help Allies in Nazi prisoner-of-war camps: They used doctored Monopoly sets to smuggle in maps, files, compasses, and real money. In this week’s episode of the Futility Closet podcast we’ll tell the story behind this clever ploy, which may have helped thousands of prisoners escape from Nazi camps.

We’ll also hear listeners’ thoughts on Jeremy Bentham’s head, Victorian tattoos, and phone-book-destroying German pirates and puzzle over murderous cabbies and moviegoers.

See full show notes …

Easy Pi

Here’s a simple algorithm that Yoshiaki Tamura and Yasumasa Kanada used to calculate π to 16 million places. It’s based on Gauss’ study of the arithmetic-geometric mean of two numbers. “Instead of using an infinite sum or product, the calculation goes round and round in a loop,” writes David Wells in The Penguin Dictionary of Curious and Interesting Numbers. “It has the amazing property that the number of correct digits approximately doubles with each circuit of the loop.” Start with these values:

\mathrm{A}=1
\mathrm{X}=1
\mathrm{B}=1/\sqrt{2}
\mathrm{C}=1/4

Then follow these instructions:

\textrm{Let}\:  \mathrm{Y}=\mathrm{A}

\textrm{Let}\:  \mathrm{A}=\displaystyle\frac{\mathrm{A}+\mathrm{B}}{2}

\textrm{Let}\:  \mathrm{B}=\sqrt{\mathrm{BY}}

\textrm{Let}\:  \mathrm{C}=\mathrm{C}-\mathrm{X}(\mathrm{A}-\mathrm{Y})^{2}

\textrm{Let}\:  \mathrm{X}=2\mathrm{X}

\textrm{PRINT}\: \displaystyle\frac{\left ( {\mathrm{A}+\mathrm{B}} \right )^{2}}{{4\mathrm{C}}}

The last instruction prints the first approximation to π; then you loop up to the top and run through the instructions again.

Running through the loop just three times gives an approximation to π that’s already correct to 5 decimal places:

Loop 1: 2.9142135
Loop 2: 3.1405797
Loop 3: 3.1415928

And running the loop a mere 19 times gives π correct to more than 1 million decimal places.

Worldly Wise

Proverbs from around the world:

  • A pretty basket does not prevent worries. (Congo)
  • Good painters need not give a name to their pictures; bad ones must. (Poland)
  • Sickness comes riding on horseback and goes away on foot. (Belgium)
  • The spectator is a great hero. (Afghanistan)
  • Those who have to go ten miles must regard nine as only halfway. (Germany)
  • The world is dark an inch ahead. (Japan)
  • Those who place their ladder too steeply will easily fall backward. (Czech Republic)
  • All the wealth of the world is in the weather. (Scotland)
  • Those whose mother is naked are not likely to clothe their aunt. (Sudan)
  • To be in the habit of no habit is the worst habit in the world. (Wales)
  • What is bad luck for one is good luck for another. (Ghana)
  • Good luck is the guardian of the stupid. (Sweden)
  • A change is as good as a rest. (England)
  • Good scribes are not those who write well, but who erase well. (Russia)
  • There is no such thing as a pretty good omelette. (France)
  • Of all the thirty-six alternatives, running away is the best. (China)

Paperwork

https://en.wikipedia.org/wiki/File:Delian_origami.svg
Image: Wikimedia Commons

Three ancient problems are famously impossible to solve using a compass and straightedge alone: doubling the cube, trisecting an angle, and squaring the circle. Surprisingly, the first two of these can be solved using origami.

In the first, doubling the cube, we’re given the edge of one cube and asked to find the edge of a second cube whose volume is twice that of the first; if the first cube’s edge length is 1, then we’re trying to find \sqrt[3]{2}. Begin by folding a square of paper into three equal panels (here’s how). Then draw up bottom corner P as shown above, so that it’s touching the top edge while the bottom of the first crease, Q, touches the second crease as shown. Now point P divides the top edge into two segments whose proportions are 1 and \sqrt[3]{2}.

https://en.wikipedia.org/wiki/File:Origami_Trisection_of_an_angle.svg
Image: Wikimedia Commons

To trisect an angle, begin by marking the angle in one corner of a square (here’s it’s CAB). Make a horizontal fold, PP’, anywhere across the square. Then divide the space below this crease in half with another crease, QQ’. Fold the bottom left corner up so that corner A touches QQ’ (at A’) and P touches AC. Now A’AB is one-third of the original angle, CAB.

The first of these constructions is due to Peter Messer, the second to Hisashi Abe. Strictly speaking, each uses creases to produce a marked straightedge, which is not allowed in classical construction, but they’re pleasingly simple solutions to these vexing problems. There’s more at origami wizard Robert Lang’s website.